posted by Rahul Chimanbhai Mehta Rrg

A proposed "in-fixable" procedure to select a large number of Jurors randomly . Say we have to select 1500 Jurors from a list of N = about 4 crore voters between age of 18 years and 120 years . . Order then in list by their assembly constituency number , booth number, serial number in section (as it is done today) . So they are all numbered from 1 to N = about 4 crore. . Say following procedure is used to select 1500 Jurors between age of 30 years to 55 years. . m = a prime number at between 0 and N selected at random in public using multiple dice-pair throw . k = a prime number at randomly between 1 lakh and 2 lakh selected at random in public using multiple dice-pair throw . select m select m + k select m + 2k .... (if number is larger than N, then divide N and take remainder i.e. modulo). . If person selected is below 30 years or above 55 years , then select next person. Repeat the process till 2000 are selected. Send summons to all 2000. At least 1900 will show up (100 may be dead of transferred) . And select first 1500 from these 1900. . === . Here is how dice pair throw can decide a number between 0 and 4 crore. . The number has 8 digits . . Two dices are thrown. One is white, another is black. And translation is done as . (W = 1 , B = 1) , digit = 0 (W = 1 , B = 2) , digit = 1 (W = 1 , B = 3) , digit = 2 (W = 1 , B = 4) , digit = 3 (W = 1 , B = 5) , digit = 4 (W = 1 , B = 6) , digit = 5 . (W = 2 , B = 1) , digit = 6 (W = 2 , B = 2) , digit = 7 (W = 2 , B = 3) , digit = 8 (W = 2 , B = 4) , digit = 9 (W = 2 , B = 5) , digit = 0 (W = 2 , B = 6) , digit = 1 . (W = 3 , B = 1) , digit = 2 (W = 3 , B = 2) , digit = 3 (W = 3 , B = 3) , digit = 4 (W = 3 , B = 4) , digit = 5 (W = 3 , B = 5) , digit = 6 (W = 3 , B = 6) , digit = 7 . (W = 4 , B = 1) , digit = 8 (W = 4 , B = 2) , digit = 9 (W = 4 , B = 3) , digit = 0 (W = 4 , B = 4) , digit = 1 (W = 4 , B = 5) , digit = 2 (W = 4 , B = 6) , digit = 3 . (W = 5 , B = 1) , digit = 4 (W = 5 , B = 2) , digit = 5 (W = 5 , B = 3) , digit = 6 (W = 5 , B = 4) , digit = 7 (W = 5 , B = 5) , digit = 8 (W = 5 , B = 6) , digit = 9 . (W = 6 , B = 1) , reject (W = 6 , B = 2) , reject (W = 6 , B = 3) , reject (W = 6 , B = 5) , reject (W = 6 , B = 6) , reject (W = 6 , B = 7) , reject . So each digit between 0 and 9 both inclusive has equal chances of getting selected. . So if 8 digits are to be selected, the dices have to be thrown 8 times (or may be 9 , 10 times if rejects show up) . If the number selected is larger then N, then dice throws have to be repeated. .

by Rahul Chimanbhai Mehta Rrg



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